As can be seen, m∠ABC=90° and BD⊥AC
The following statements are true based on the given information.
1. (BD)^2=AD*DC,2.(AB)^2=AD*AC ,3.(BC)^2=CD*CA , 4.AB*BC=AC*BD
Proof for the the first statement:
Since m∠BDC=90
m∠DBC+m∠C=90 (corollary to the triangle sum theorem)
and SInce m∠ABC=90
m∠A+m∠C=90 (corollary to the triangle sum theorem)
m∠DBC=m∠A
for the same reason
m∠A+m∠ABD=90
m∠A+m∠C=90
m∠C=m∠ABD
Since ∠C≌∠ABD and m∠BDA=m∠BDC=90
By the Angle-Angle Similarity Postulate
△ABD∽△BCD
Therefore AD/BD=BD/CD
(BD)^2=AD*DC
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